battle, nineteenth century
Battle of Puketutu
Battle of Puketutu was a battle fought on 8 May 1845 at Bay of Islands, in what is now New Zealand. It was part of the Flagstaff War, which ran from 1845 to 1846. The recorded result: Māori victory.
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Where it sits in the Flagstaff War
Record
| Date | 8 May 1845 | |
|---|---|---|
| Place | Bay of Islands, New Zealand 35.339S, 173.817E | |
| Kind | Battle, nineteenth century | |
| Strength | British Army; 320 soldiers; 40 militia; Royal Navy; 87 sailors & marines; Allied Māori; 300 warriors (Nene's war party) | Māori; 200 warriors (Heke's war party); 140 warriors (Kawiti's war party) |
| Casualties and losses | 13 killed; 30–40 wounded | 30 killed; 50 wounded |
| Commanders |
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Nearest engagements
- Battle of Ohaeawai 1845, 5.4 km SE
- Battle of Kororareka 1845, 29 km E
- Battle of Ruapekapeka date unknown, 32 km SE
- Moremonui 1807, 63 km S
- Battle of Hingakaka 1791, 322 km SE
In the same war
- Before: Battle of Kororareka 11 March 1845
- After: Battle of Ohaeawai July 1845
- All 4 engagements of Flagstaff War
Elsewhere in 1845
- Battle of Vuelta de Obligado Argentina
- Battle of Mudki India
- Battle of Dargo Russia
- Battle of Ferozeshah India
- Battle of Sidi-Brahim Algeria
Battle of Puketutu is one of 3,694 engagements of the 19th century in the atlas and one of 12 in present-day New Zealand.
Sources
Identity, coordinates, dates and the war from Wikidata Q116413774, released under CC0. Result, belligerents, commanders, strength and casualties from the infobox of the English Wikipedia article Battle of Puketutu, revision 1371315590, read 2026-11-14, licensed CC BY-SA 4.0; the article's text is not reproduced here. Present-day country and state from Natural Earth. Dates before 1582 follow the Julian calendar as recorded.